Geometry problem

A parking lot has a rectangular area of 40,000 yards square. The length is 200 yards more than twice the width. Find the dimensions.

One Answer:
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Let the length be y and the width be x.

xy = 40000

The length is 200 yards more than twice the width:

y=2x+200

Substitute 2x+200 in for y:

x(2x+200) = 40000

Solve the equation and ignore the negative value:

x(2x+200) = 40000

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