Find to the nearest tenth, the measure of the third side of each triangle
In triangle ABC, b=12.4, c=8.70, and m<A=23
Show how to get the answer please
Use the law of cosines:
cos A = (b^2+c^2-a^2)/(2bc)
a^2 = b^2+c^2-2bc cos (A)
a = sqrt(b^2+c^2-2bc cos(A)
Since the Algebra Calculator uses radians, I had to convert 23 degrees to 23*PI/180 radians in the link below.
link
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