A projectile follows a parabolic path whose height, in meters, is given by the function f(x)= -x^2 + 2x + 2 Find the maximum distance that the projectile may cover.


the vertex is at x=-b/(2a)

b=2 and a=-1

x=-b/(2a)

x=-2/(2*-1)

x=1

so the highest it'll go is at x=1

f(1) = -1^2+2(1)+2

f(1) = 3

the maximum height is 3 meters

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