2^(x+3)=7 I'm not even sure where to begin.. |
let me try: 2^(x+3)=7 you want to take the logarithm of both sides (you can learn more about logarithms at https://www.khanacademy.org/math/algebra/logarithms-tutorial/logarithm_basics/v/logarithms log(2^(x+3)) = log(7) (x+3)*log(2) = log(7) (for any numbers b and c: log(b^c) = c * log(b) ) x+3 = log(7)/log(2) x= log(7)/log(2)-3 x= ?0.192645 (approx) You can check your answer using @ in the calculator: 2^(x+3)=7 @ log(7)/log(2)-3 |